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Get StartedGiven a binary tree, in-place convert it into its sum tree. Each node’s value is equal to the sum of all elements present in its left and right subtree in a sum tree. Consider the value of an empty node as 0.
Given a binary tree, print all cousins of a given node. Two nodes of a binary tree are cousins of each other only if they have different parents, but they have the same level.
Given a binary tree, determine if two given nodes are cousins of each other or not. Two nodes of a binary tree are cousins of each other only if they have different parents, but they have the same level.
Given a binary tree, check if it is a complete binary tree or not. A complete binary tree is a binary tree in which every level, except possibly the last, is filled, and all nodes are as far left as possible.
Given a binary tree and a node in it, write an efficient algorithm to find its next node at the same level as the node.
Given a binary tree, print the top view of it. Assume the left and right child of a node makes a 45–degree angle with the parent.
Given a binary tree, print the bottom view of it. Assume the left and right child of a node makes a 45–degree angle with the parent.
Given a binary tree, write an efficient algorithm to print its left view. For example, the left view of the following binary tree is 1, 2, 4, 7.
Given a binary tree, write an efficient algorithm to print all nodes in a specific order. We need to print nodes of every level in alternating left and right.
Given a binary tree, print its nodes level by level in reverse order, i.e., print all nodes present at the last level first, followed by nodes of the second last level, and so on… Print nodes at any level from left to right.
Given a binary tree, print its nodes level by level in spiral order, i.e., all nodes present at level 1 should be printed first from left to right, followed by nodes of level 2 right to left, followed by nodes of level 3 from left to right and so on…
Given a binary tree, print its nodes level by level, i.e., print all nodes of level 1 first, followed by nodes of level 2 and so on… Print nodes for any level from left to right.