Initialize List in a single line in C#

This post will discuss how to initialize a List in a single line in C#.

We can initialize a list inline in C# using the new List<Type> { Value1, Value2, .., ValueN }; syntax. This is demonstrated below:

using System;

using System.Collections.Generic;

public class Example

{

public static void Main()

{

List<string> strings = new List<string> { "Blue", "Red", "Yellow" };

Console.WriteLine(String.Join(", ", strings)); // Blue, Red, Yellow

}

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The List<T> provides a constructor that initializes a new instance of the List<T> class containing elements copied from the specified collection. The following example demonstrates this by creating an array of strings and passing it to the List<T> constructor.

using System;

using System.Collections.Generic;

public class Example

{

public static void Main()

{

string[] colors = { "Blue", "Red", "Yellow" };

List<string> strings = new List<string>(colors);

Console.WriteLine(String.Join(", ", strings)); // Blue, Red, Yellow

}

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We can do this in a single step by combining the list constructor with the array initializer syntax.

using System;

using System.Collections.Generic;

public class Example

{

public static void Main()

{

List<string> strings = new List<string>(new string[] { "Blue", "Red", "Yellow" });

Console.WriteLine(String.Join(", ", strings)); // Blue, Red, Yellow

}

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That’s all about initializing a List in a single line in C#.

Initialize List in a single line in C#

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